Optimal. Leaf size=282 \[ \frac{77 a^{9/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right ),\frac{1}{2}\right )}{60 b^{15/4} \sqrt{a+b x^4}}+\frac{77 a^2 x \sqrt{a+b x^4}}{30 b^{7/2} \left (\sqrt{a}+\sqrt{b} x^2\right )}-\frac{77 a^{9/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{30 b^{15/4} \sqrt{a+b x^4}}+\frac{11 x^7 \sqrt{a+b x^4}}{18 b^2}-\frac{77 a x^3 \sqrt{a+b x^4}}{90 b^3}-\frac{x^{11}}{2 b \sqrt{a+b x^4}} \]
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Rubi [A] time = 0.114551, antiderivative size = 282, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {288, 321, 305, 220, 1196} \[ \frac{77 a^2 x \sqrt{a+b x^4}}{30 b^{7/2} \left (\sqrt{a}+\sqrt{b} x^2\right )}+\frac{77 a^{9/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{60 b^{15/4} \sqrt{a+b x^4}}-\frac{77 a^{9/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{30 b^{15/4} \sqrt{a+b x^4}}+\frac{11 x^7 \sqrt{a+b x^4}}{18 b^2}-\frac{77 a x^3 \sqrt{a+b x^4}}{90 b^3}-\frac{x^{11}}{2 b \sqrt{a+b x^4}} \]
Antiderivative was successfully verified.
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Rule 288
Rule 321
Rule 305
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{x^{14}}{\left (a+b x^4\right )^{3/2}} \, dx &=-\frac{x^{11}}{2 b \sqrt{a+b x^4}}+\frac{11 \int \frac{x^{10}}{\sqrt{a+b x^4}} \, dx}{2 b}\\ &=-\frac{x^{11}}{2 b \sqrt{a+b x^4}}+\frac{11 x^7 \sqrt{a+b x^4}}{18 b^2}-\frac{(77 a) \int \frac{x^6}{\sqrt{a+b x^4}} \, dx}{18 b^2}\\ &=-\frac{x^{11}}{2 b \sqrt{a+b x^4}}-\frac{77 a x^3 \sqrt{a+b x^4}}{90 b^3}+\frac{11 x^7 \sqrt{a+b x^4}}{18 b^2}+\frac{\left (77 a^2\right ) \int \frac{x^2}{\sqrt{a+b x^4}} \, dx}{30 b^3}\\ &=-\frac{x^{11}}{2 b \sqrt{a+b x^4}}-\frac{77 a x^3 \sqrt{a+b x^4}}{90 b^3}+\frac{11 x^7 \sqrt{a+b x^4}}{18 b^2}+\frac{\left (77 a^{5/2}\right ) \int \frac{1}{\sqrt{a+b x^4}} \, dx}{30 b^{7/2}}-\frac{\left (77 a^{5/2}\right ) \int \frac{1-\frac{\sqrt{b} x^2}{\sqrt{a}}}{\sqrt{a+b x^4}} \, dx}{30 b^{7/2}}\\ &=-\frac{x^{11}}{2 b \sqrt{a+b x^4}}-\frac{77 a x^3 \sqrt{a+b x^4}}{90 b^3}+\frac{11 x^7 \sqrt{a+b x^4}}{18 b^2}+\frac{77 a^2 x \sqrt{a+b x^4}}{30 b^{7/2} \left (\sqrt{a}+\sqrt{b} x^2\right )}-\frac{77 a^{9/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{30 b^{15/4} \sqrt{a+b x^4}}+\frac{77 a^{9/4} \left (\sqrt{a}+\sqrt{b} x^2\right ) \sqrt{\frac{a+b x^4}{\left (\sqrt{a}+\sqrt{b} x^2\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} x}{\sqrt [4]{a}}\right )|\frac{1}{2}\right )}{60 b^{15/4} \sqrt{a+b x^4}}\\ \end{align*}
Mathematica [C] time = 0.0261316, size = 80, normalized size = 0.28 \[ \frac{x^3 \left (-77 a^2 \sqrt{\frac{b x^4}{a}+1} \, _2F_1\left (\frac{3}{4},\frac{3}{2};\frac{7}{4};-\frac{b x^4}{a}\right )+77 a^2-11 a b x^4+5 b^2 x^8\right )}{45 b^3 \sqrt{a+b x^4}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.012, size = 157, normalized size = 0.6 \begin{align*} -{\frac{{x}^{3}{a}^{2}}{2\,{b}^{3}}{\frac{1}{\sqrt{ \left ({x}^{4}+{\frac{a}{b}} \right ) b}}}}+{\frac{{x}^{7}}{9\,{b}^{2}}\sqrt{b{x}^{4}+a}}-{\frac{16\,a{x}^{3}}{45\,{b}^{3}}\sqrt{b{x}^{4}+a}}+{{\frac{77\,i}{30}}{a}^{{\frac{5}{2}}}\sqrt{1-{i{x}^{2}\sqrt{b}{\frac{1}{\sqrt{a}}}}}\sqrt{1+{i{x}^{2}\sqrt{b}{\frac{1}{\sqrt{a}}}}} \left ({\it EllipticF} \left ( x\sqrt{{i\sqrt{b}{\frac{1}{\sqrt{a}}}}},i \right ) -{\it EllipticE} \left ( x\sqrt{{i\sqrt{b}{\frac{1}{\sqrt{a}}}}},i \right ) \right ){b}^{-{\frac{7}{2}}}{\frac{1}{\sqrt{{i\sqrt{b}{\frac{1}{\sqrt{a}}}}}}}{\frac{1}{\sqrt{b{x}^{4}+a}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{14}}{{\left (b x^{4} + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{b x^{4} + a} x^{14}}{b^{2} x^{8} + 2 \, a b x^{4} + a^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 2.59233, size = 37, normalized size = 0.13 \begin{align*} \frac{x^{15} \Gamma \left (\frac{15}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{3}{2}, \frac{15}{4} \\ \frac{19}{4} \end{matrix}\middle |{\frac{b x^{4} e^{i \pi }}{a}} \right )}}{4 a^{\frac{3}{2}} \Gamma \left (\frac{19}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{14}}{{\left (b x^{4} + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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